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John Rumbaugh

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John Rumbaugh

Birth
Virginia, USA
Death
7 Feb 1876 (aged 64)
Eldora, Hardin County, Iowa, USA
Burial
Pleasant Township, Hardin County, Iowa, USA Add to Map
Memorial ID
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When John Rumbaugh was born on November 1, 1811, in Virginia, his father, George, was 22 and his mother, Elizabeth, was 22. He married Mary Elizabeth Higgenbotham in 1833 in Greene, Ohio. They had 12 children in 31 years. He died on February 7, 1876, in Eldora, Iowa, at the age of 64, and was buried there.
Contributor: Mark Adamson (50326234)
When John Rumbaugh was born on November 1, 1811, in Virginia, his father, George, was 22 and his mother, Elizabeth, was 22. He married Mary Elizabeth Higgenbotham in 1833 in Greene, Ohio. They had 12 children in 31 years. He died on February 7, 1876, in Eldora, Iowa, at the age of 64, and was buried there.
Contributor: Mark Adamson (50326234)

Inscription

65y 3m 7d



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  • Created by: Grasser
  • Added: Jan 30, 2012
  • Find a Grave Memorial ID:
  • Find a Grave, database and images (https://www.findagrave.com/memorial/84240230/john-rumbaugh: accessed ), memorial page for John Rumbaugh (1 Nov 1811–7 Feb 1876), Find a Grave Memorial ID 84240230, citing Point Pleasant Cemetery, Pleasant Township, Hardin County, Iowa, USA; Maintained by Grasser (contributor 47600919).